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Question

In a potentiometer arrangement, a cell of emf 1.25 V gives a balancepoint at 35.0 cm length of the wire. If the cell is replaced by anothercell and the balance point shifts to 63.0 cm, what is the emf of thesecond cell?

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Solution

Given: The emf of the cell is 1.25V, the balance point of potentiometer is 35cm and after changing the cell the new balance point is 63cm.

The balance condition of a potentiometer is given as,

E 1 E 2 = l 1 l 2

Where, the emf of cell in the first case is E 1 , after changing the cell the new emf is E 2 , the balance point of potentiometer in first case is l 1 and the balance point after changing cell is l 2 .

By substituting the given values in the above equation, we get

1.25 E 2 = 25 63 E 2 =2.25V

Thus, the emf of the second cell is 2.25V.


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