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Question

In a potentiometer experiment, the balancing with a cell is at length $$240 cm$$. On shunting the cell with a resistance of $$2\Omega$$ , the balancing length becomes $$120 cm$$. The internal resistance of the cell is


A
1Ω
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B
0.5Ω
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C
4Ω
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D
2Ω
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Solution

The correct option is C 2$$\Omega$$
Internal resistance of a cell $$r$$ is given by
$$r = R [\dfrac {l_1}{l_2}-1]$$
$$\Rightarrow r = 2 [\dfrac {240}{120}-1]$$
$$\Rightarrow r = 2 \times 1 = 2 \Omega$$

Physics

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