Question

# In a potentiometer experiment, the balancing with a cell is at length $$240 cm$$. On shunting the cell with a resistance of $$2\Omega$$ , the balancing length becomes $$120 cm$$. The internal resistance of the cell is

A
1Ω
B
0.5Ω
C
4Ω
D
2Ω

Solution

## The correct option is C 2$$\Omega$$Internal resistance of a cell $$r$$ is given by$$r = R [\dfrac {l_1}{l_2}-1]$$$$\Rightarrow r = 2 [\dfrac {240}{120}-1]$$$$\Rightarrow r = 2 \times 1 = 2 \Omega$$Physics

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