In a queue, A is eighteenth from the front while B is sixteenth from the back. If C is twenty-fifth from the front and is exactly in the middle of A and B, then how many persons are there in the queue?

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None of the above

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Solution

The correct option is C 47
Number of persons between A and C = 25 - 18 = 7
$∴$ The position of C from front = 18 + 7 = $25^{t h}$
Also, number of persons between C and B = 7
$∴$ The position of C from the back = 16 + 7 = 23rd
$∴$ Total number of persons = position of C from front + position of C from back -1
25 + 23 - 1 = 47
Hence, the required answer is (3)

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