  Question

# Question 1 In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass. Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water

Solution

## In the given reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbon dioxide, and water Sodium carbonate + Ethanoic acid → Sodium ethanoate + Carbon dioxide + Water Mass of sodium carbonate = 5.3g (given) Mass of ethanoic acid = 6 g (given) Mass of carbon dioxide = 2.2 g (given) Mass of water = 0.9 g (given) Mass of sodium ethanoate = 8.2 g (given) Now total mass before reaction = (5.3 g + 6 g) = 11.3 g Now total mass after reaction = (8.2 g + 2.2 g + 0.9 g) = 11.3 g Total mass before reaction = Total mass after reaction Therefore the given observation is in agreement with the law of conservation of mass.  Suggest corrections  Similar questions
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