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Question 1
In a reaction, 5.3 g of sodium carbonate reacted with 6 g of ethanoic acid. The products were 2.2 g of carbon dioxide, 0.9 g water and 8.2 g of sodium ethanoate. Show that these observations are in agreement with the law of conservation of mass.

Sodium carbonate + Ethanoic acid Sodium ethanoate + Carbon dioxide + Water


Solution

In the given reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbon dioxide, and water

Sodium carbonate + Ethanoic acid Sodium ethanoate + Carbon dioxide + Water

Mass of sodium carbonate = 5.3g (given)

Mass of ethanoic acid = 6 g (given)

Mass of carbon dioxide = 2.2 g (given)

Mass of water = 0.9 g (given)

Mass of sodium ethanoate = 8.2 g (given)

Now total mass before reaction = (5.3 g + 6 g) = 11.3 g

Now total mass after reaction = (8.2 g + 2.2 g + 0.9 g) = 11.3 g

Total mass before reaction = Total mass after reaction

Therefore the given observation is in agreement with the law of conservation of mass.

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