Question

In a reaction, 5.3 g of sodium carbonate reacted with 6 g of acetic acid. The products were 2.2 g of carbon dioxide, 0.9 g of water and 8.2 g of sodium acetate. Show that these observations are in agreement with the law of conservation of mass.
Sodium Carbonate + Acetic Acid $\to$Sodium Acetate + Carbon Dioxide + Water

Answer 1

In the given reaction, sodium carbonate reacts with acetic acid to produce sodium acetate, carbon dioxide, and water.
Sodium Carbonate + Acetic Acid $\to$Sodium Acetate + Carbon Dioxide + Water
Mass of Sodium Carbonate = 5.3 g (Given)

Mass of Acetic Acid = 6 g (Given)

Mass of Sodium Acetate = 8.2 g (Given)

Mass of Carbon Dioxide = 2.2 g (Given)

Mass of Water = 0.9 g (Given)

Now, total mass before the reaction = Mass of (Sodium Carbonate + Acetic Acid) = (5.3 + 6) g

= 11.3 g

And, total mass after the reaction = Mass of (Sodium Acetate + Carbon Dioxide + Water) = (8.2 + 2.2 + 0.9) g

= 11.3 g

∴ Total mass before the reaction = Total mass after the reaction

Hence, the given observations are in agreement with the law of conservation of mass.