CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

In a reaction A products, the rate is doubled when the concentration of A is increased 4 times. If 50% of the reaction occurs in 1414 sec , how long would it takes for the completion of 75% reaction.


A

4242sec

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

2825 sec

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

2414 sec

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

2121 sec

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C

2414 sec


Order= 12


First t12=1414sec;

therefore second t12
(t121an1)=14142=1000sec

total time for 75% reaction is 1414+1000=2414 sec


flag
Suggest Corrections
thumbs-up
6
mid-banner-image
mid-banner-image
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Factors Affecting Rate of a Chemical Reaction
CHEMISTRY
Watch in App
Join BYJU'S Learning Program