In a rectangle ABCD - AB -20 cm - - BAC -60- Then- side BC -A- 20 -3 cmB- 10 -3 cmC- 20 cmD- 10 cm

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In a rectangl...

Question

In a rectangle ABCD, AB = 20 cm, $∠$ BAC = $60^{\circ}$ . Then, side BC =

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Solution

The correct option is A
Given: AB = 20 cm

In the above rectangle ABCD, let the breadth 'BC' be = x
$t a n 60^{\circ} = \frac{B C}{A B} = \frac{x}{20}$
$\sqrt{3} = \frac{x}{20}$
$\Rightarrow x = 20 \sqrt{3}$

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The correct option is A
Given: AB = 20 cm

In the above rectangle ABCD, let the breadth 'BC' be = x
$t a n 60^{\circ} = \frac{B C}{A B} = \frac{x}{20}$
$\sqrt{3} = \frac{x}{20}$
$\Rightarrow x = 20 \sqrt{3}$