In a resonance tube experiment, resonance occurs first at 32.0cm and then at 100.0cm. What is the percentage error in the measurement of end correction?
A
2.5 %
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B
5 %
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C
7.5 %
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D
10 %
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Solution
The correct option is D 10 % We know that, e=l3−3l12=2.0cm and de=dl3+3dl12 % error=dl3+3dl12×e×100
As the values of l1 and l2, are given with 1 significant figure after decimal point, their least count will be 0.1cm. So, dl1=dl2=0.1cm