In a restaurant, WiFi signal has to be provided only to the deluxe class. Signal reaches each of the customer upto a distance of 21 m from the antenna and the total area for which signal to be provided is 231 $m^{2}$ . What is the angle (in degrees) at which the signal has to be spread over a sector by the antenna?

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Solution

The correct option is A
60

Given , Radius r = 21 m

Area of sector

$= \frac{θ}{360} \times π \times r^{2}$

$\Rightarrow 231 = \frac{22 \times 21^{2} \times θ}{7 \times 360}$

$θ = 60^{\circ}$

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Similar questions

In a restaurant, WiFi signal has to be provided only to the deluxe class. Signal reaches each of the customer upto a distance of 21 m from the antenna and the total area for which signal to be provided is 231 $m^{2}$ . What is the angle (in degrees) at which the signal has to be spread over a sector by the antenna?

I = \frac{P}{4 π r^{2}}

At a large distance

r

from a radio antenna, the intensity of the radio signal

I

is related to the power of the signal

P

by the formula above.

Which of the following expresses the square of the distance from the radio antenna in terms of the

intensity of the radio signal and the power of the signal?

Q. For the same signal emitted by a radio antenna, Observer A measures its intensity to be

16

times the intensity measured by Observer B. The distance of Observer A from the radio antenna is what fraction of the distance of Observer B from the radio antenna?

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The correct option is A 60 Given , Radius r = 21 m Area of sector =θ360 ×π×r2 ⇒231=22×212×θ7×360 θ =60∘

The correct option is A
60

Given , Radius r = 21 m

Area of sector

$= \frac{θ}{360} \times π \times r^{2}$

$\Rightarrow 231 = \frac{22 \times 21^{2} \times θ}{7 \times 360}$

$θ = 60^{\circ}$