In a right angled triangle ABC (right angled at B), find the value of tan A × tan C.
[2 Marks]

Open in App

Solution

From figure, tan A= $\frac{B C}{A B}$

and tan C = $\frac{A B}{B C}$

[1 Mark]

So, tan A × tan C= $\frac{B C}{A B} \times \frac{A B}{B C} = 1.$
[1 Mark]

Suggest Corrections

Similar questions

In a right angled triangle ABC (right angled at B)

The value of tan A tan C=__

In a right angle triangle ABC (right angled at B), find the value of $tan A \times tan C$ .

In a right angled triangle ABC (right angled at B),

the value of tan A ✕ tan C = _______.

5 \times s i n A = 3

In a right angle triangle ABC (right angle at B)

The value of tan A tan C=__

Join BYJU'S Learning Program