In a right-triangle, the hypotenuse is 6 m more than twice the shortest side. If the third side is 2 m less than the hypotenuse, then the length of hypotenuse is ___ m .
Let x be the length of the shortest side. Then, by question, hypotenuse and the third side measure 2x+6 m and (2x+6)−2=2x+4 m respectively.
Using Pythagoras' theorem, we have
Ignoring the negative solution as length of a side cannot be negative, we have x = 10 m (shortest side).
Hypotenuse, 2x+6=2(10)+6=20+6=26 m.