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Question

In a satellite if the time of revolution is T, then its kinetic energy is proportional to

A
1T
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B
1T2
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C
1T3
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D
T23
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Solution

The correct option is D T23
According to Kepler's third law which states that:
Time period T r32 where r = radius of the circular path/orbit around which the satellite moves
r T23
And kinetic energy K.E 1r
K.E1T23 or,
K.ET23

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