Question

# In a series resonant circuit, having L,C,R as its elements, the resonant current is $$i$$. The power dissipated in the circuit at resonance is

A
i2lω
B
i2R
C
zero
D
i2Cω

Solution

## The correct option is A $$i^2R$$Given series resonant circuit having $$L,C,R$$ as its elementsThe resonant current is $$i$$The effective resistance is $$\sqrt { { R }^{ 2 }+{ (Lw-\frac { 1 }{ Cw } ) }^{ 2 } }$$But at resonance $$w=\frac{1}{\sqrt{LC}}$$So we get effective resistance as $$R$$The power dissipated is $$i^{2}R$$Therefore option $$B$$ is correctPhysics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More