Question

In a series resonant circuit, having L,C,R as its elements, the resonant current is $i$. The power dissipated in the circuit at resonance is

• A. $i^{2}l\omega$
• B. $i^{2}R$
• C. zero
• D. $i^{2}C\omega$

Answer 1

Answer: (B)

$i^{2}R$

Given series resonant circuit having $L,C,R$ as its elements

The resonant current is $i$

The effective resistance is $\sqrt{R^2+{(Lw-\frac{1}{Cw})}^2}$

But at resonance $w=\frac{1}{\sqrt{LC}}$

So we get effective resistance as $R$

The power dissipated is $i^{2}R$

Therefore option $B$ is correct