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Question

In a series resonant circuit, having L,C,R as its elements, the resonant current is $$i$$. The power dissipated in the circuit at resonance is


A
i2lω
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B
i2R
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C
zero
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D
i2Cω
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Solution

The correct option is A $$i^2R$$
Given series resonant circuit having $$L,C,R$$ as its elements
The resonant current is $$i$$
The effective resistance is $$\sqrt { { R }^{ 2 }+{ (Lw-\frac { 1 }{ Cw } ) }^{ 2 } } $$
But at resonance $$w=\frac{1}{\sqrt{LC}}$$
So we get effective resistance as $$R$$
The power dissipated is $$i^{2}R$$
Therefore option $$B$$ is correct

Physics

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