In a set of the given reactions, acetic acid yielded a product $C$ .
$C H_{3} C O O H + P C l_{5} ⟶ A C_{6} H_{6} - --- \to A l C l_{3} B C_{2} H_{5} M g B r / H_{3} O^{\oplus} - --------------- \to e t h e r C$ product $C$ would be:

C H_{3} C H (O H) C_{2} H_{5}

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C H_{3} C O C_{6} H_{5}

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C H_{3} C H (O H) C_{6} H_{5}

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C H_{3} - C_{2} H_{5} ∣ C (O H) C_{6} H_{5}

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Solution

The correct option is D $C H_{3} - C_{2} H_{5} ∣ C (O H) C_{6} H_{5}$
In the following set of reactions, acetic acid yielded product C which is $C H_{3} - C_{2} H_{5} ∣ C (O H) C_{6} H_{5}$ .

$C H_{3} C O O H + P C l_{5} ⟶ C H_{3} C O C l A C_{6} H_{6} - --- \to A l C l_{3} C H_{3} C O C_{6} H_{5} B C_{2} H_{5} M g B r / H_{3} O^{\oplus} - --------------- \to e t h e r$

$C H_{3} - C_{2} H_{5} ∣ C (O H) C_{6} H_{5} C$
Acetic acid reacts with phosphorus pentachloride to form acetyl chloride (compound A).
Friedel craft's acylation of benzene in presence of anhydrous aluminum chloride gives acetophenone.
Acetophenone reacts with grignards reagent to form tertiary alcohol (compound C).

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