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Question

# In a simple wood machine, two unequal masses m1 and m1 are connected by a string going over a clamped light smooth pulley. In a typical arrangement (In the figure) m1=300g and m2=600g. The system is released from rest.

A
7.8 N
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B
8.7 N
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C
5.1 N
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D
2.1 N
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Solution

## The correct option is A 7.8 NFor block 1T−(m1g+m1a)=0−−−−−−(1)T=m1g+m1aFor block 2,T+m2a−m2g=0---------- (2)T=m2g−m2aFrom en (1) and (2),m1g+m1a+m2a−m2g=0From eqn (1) a(m1+m2)=g(m2−m1)a=g(m2−m1m1+m2)a=9.8(0.6−0.30.6+0.3)=3.260m/s2(a) T= 2s, a= 3.260 m/s2, speed u=0s=ut+12at2=0+12(3.260)2×22=6.5m(b) From (1), T=m1(g+a)=0.3(9.8+3.260)=3.9N(C)F-2T=0F=2T= 2×3.9=7.8N

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