In a single fixed pulley, the velocity ratio is always less than the mechanical advantage.

True

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False

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Solution

The correct option is B
False

We know, that incase of single fixed pulley, distance by the effort is equal to distance moved by the load upward. If $d_{E}$ = d, $d_{L}$ = d

V.R = $\frac{d_{E}}{d_{L}}$ = $\frac{d}{d}$ = 1

Since, L = T and E = T

But, M.A = $\frac{L o a d}{E f f o r t}$ = $\frac{T}{T}$ = 1

This is applicable in ideal conditions only. In actual practice to lift load, effort needed is more than load. Hence, V.R > M.A

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Similar questions

Give reasons for the following :

(a) In a single fixed pulley, the velocity ratio is always more than the mechanical advantage.

(b) The efficiency of a movable pulley is always less than $100 %$ .

(d) The lower block of a block and tackle pulley system must be of negligible weight.

A single fixed pulley is used because it :

(a) ha sthe mechanical advantage greater than 1

(b) has the velocity ratio less than 1

(d) helps to apply the effort in a convenient direction.

The mechanical advantage of an ideal single movable pulley is :

(a) 1 (b) 2

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