Question

# In a single slit diffraction experiment, light of wavelength λ passes through a slit of width a and produces a diffraction pattern with I0 as the intensity of the central maximum. Find the ratio of intensity at a point midway between second and third minima to the intensity at the central maxima.

A
122
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B
755
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C
493025
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D
15
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Solution

## The correct option is C 493025Intensity at a point is given by I=I0sin2ββ2 Where, β=πasinθλ I0→ Intensity at central maximum. ⇒ The point midway between second minima and third minima will be second maximum. ⇒sinθ=5λ2a [For second maxima] ⇒β=5π2 ⇒I=I0(sin(5π/2)5π/2)2 ⇒I=I0(2×75×22)2⇒II0=493025 Hence, option (C) is correct.

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