Question

# In a solid $$''AB''$$ having $$NaCl$$ type structure $$''A''$$ atoms occupy the FCC lattice points of the cubic unit cell. If all the face-centered atoms along one of the axis are removed, then the resultant stoichiometry of the solid is :

A
AB2
B
A2B
C
A4B3
D
A3B4

Solution

## The correct option is C $$A_{3}B_{4}$$Since $$A$$ atoms occupy the corners of the cubic unit cell, the number of atoms occupying the corners is $$1$$. If all the face-centred atoms along one of the axes are removed, then only $$4$$ faces remain, which counts in total to $$2$$ atoms of $$A$$. $$B$$ is present in octahedral voids, so the total number of atoms of $$B$$ is $$4$$.Hence, the stoichiometry is $$A_3B_4$$.Hence, option is D.Chemistry

Suggest Corrections

0

Similar questions
View More

People also searched for
View More