In a step-up transformer, the ratio of turns of primary to secondary coils is 1:10 and primary voltage is 230V. If the load current is 2A, the current in the primary coil is:

20 A

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10 A

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2 A

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1 A

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Solution

The correct option is A 20 A
Given

$N_{1} : N_{2} = 1 : 10$

Where

$N_{1} =$ Number of turns in primary coil

$N_{2} =$ Number of turns in secondary coil

Primary voltage $V_{1} = 230 V$

Secondary current $I_{2} = 2 A$
It is asked to find out the current through the primary coil, $I_{1}$

We have

$\frac{N_{1}}{N_{2}} = \frac{I_{2}}{I_{1}}$

Substituting the values in the above equation we get,
$\frac{1}{10} = \frac{2}{I_{1}}$

$I_{1} = 20$

Hence current thorough primary coil is $20 A$

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