CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

In a test experiment on a model aeroplane in a wind tunnel, the flow speeds on the upper and lower surfaces of the wing are 70ms1 and 63ms1 respectively. What is the lift on the wing if its area is 2.5 m2? Take the density of air to be 1.3 kg m3.


Solution

Speed of wind on the upper surface of the wing, V1=70m/s
Speed of wind on the lower surface of the wing, V2=63m/s
Area of the wing, A=2.5m2
Density of air, ρ=1.3kgm3
According to Bernoulli’s theorem, we have the relation:
P1+12ρV21=P2+12ρV22P2P1=12ρ(V21V22)
Where,
P1 = Pressure on the upper surface of the wing
P2= Pressure on the lower surface of the wing
The pressure difference between the upper and lower surfaces of the wing provides lift to the aeroplane.
Lift on the wing =(P2P1)A
=12ρ(V21V22)A=121.3((70)3(63)2)×2.5
=1512.87
=1.51×103N
Therefore, the lift on the wing of the aeroplane is 1.51×103N.
 

flag
 Suggest corrections
thumbs-up
 
0 Upvotes


Similar questions
View More


Same exercise questions
View More



footer-image