Question

In a transistor biased in the common-emitter mode the emitter current is

• A. Much smaller than base current
• B. Much larger than base current
• C. Nearly equal to the base current
• D. Much smaller than the collector current

Answer 1

Answer: (B)

Much larger than base current

$I_C=$collector current, $I_B=$base current, $I_E=$emitter current

In common emitter mode,

$I_E=I_C+I_B$

Also,

$\beta =\frac{I_C}{I_B}$

and $\beta$ is very large.

So, $I_B$ is very small.

So, $I_E$ is much larger than $I_B$.