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Question

In a ABC,(a+b+c)(tanA2+tanB2) is


Solution

The correct option is A


(a+b+c)(tanA2+tanB2)
=2s(tanA2+tanB2)
=2s(s(sa)+s(sb))=2((sa)+(sb))
=2(sb+sa(sa)(sb))=2(c(sa)(sb))
=2c cotC2

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