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Question

In a triangle ABC, if 2AC=3CB and 2OA+3OB=λOC, then λ is

A
5.000
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B
5
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C
5.00
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D
5.0
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Solution

Given, ​​2AC=3CB
AC=OCOAOA=OCAC
CB=OBOCOB=CB+OC
2OA+3OB=5OC2AC+3CB
2OA+3OB=5OC (2AC=3CB)
λ=5

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