Question

In a $△ABC$, if $\angle A={54}^o$ and $\angle C={67}^o$, find the measure of $\angle B$.

Answer 1

Given in $\Delta ABC$, $\angle A={54}^o$ and $\angle C={67}^o$.

Then $\angle C={180}^o-({54}^o+{67}^o)={59}^o$. [ Since the sum of interior angles of a triangle is ${180}^o$]