Question

In a turning process using orthogonal tool geometry, a chip length of 100 mm is obtained for an uncut chip length of 250 mm. The cutting conditions are cutting speed = 30 m/min, rake angle = 20°.
The shear plane angle is degrees (round off to one decimal place).

Answer 1

Given, $I_c=100mm,l=250mm,\alpha =20{}^{\circ }$

$\tau =\frac{I_c}{l}=\frac{100}{250}=0.4$

$\tan \varphi =\frac{r\cos \alpha }{1-r\sin \alpha }=\frac{0.4\cos 20{}^{\circ }}{1-0.4\times \sin 20{}^{\circ }}=0.4354$

$\varphi ={\tan }^{-1}\left(0.4354\right)=23.5{}^{\circ }$