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Question

In a Young's double slit experiment, the fringe width is found to be 0.4mm. If the whole apparatus is immersed in water of refractive index 43 without disturbing the geometrical arrangement, the new fringe width will be

A
0.30mm
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B
0.40mm
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C
0.53mm
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D
450μm
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Solution

The correct option is D 0.30mm
The formula for the fringe width is :
β=λDd;

Bλ

We also know that the wavelength is inversely proportional to the refractive index of the medium.
So, λ=λμ
So ,λ=3λ4
So, the ratio can be obtained as:
ββ=λλ
β=0.44/3

β=0.3 mm

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