Question

# In a Young's doubleslit experiment, first maxima is observed at a fixed point P on the screen. Now, the screen is continuously moved away from the plane of slits. The ratio of intensity at point P to the intensity at point O (centre of the screen)

A
remains constant
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B
keeps on decreasing
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C
first decreases and then increases
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D
first decreases and then becomes constant
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Solution

## The correct option is C first decreases and then increasesPosition of 1st Maxima:x=D×λdAs D increases, the Maxima at P will go upwards.We know that There is a Minima between O and P.Hence Point P will observe a decrease in intensity till the position of minima is reached and after that the Intensity will increase due to the Central Maxima. Answer is C: first decreases and then increases

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