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Question

In a Youngs double experiment, the slits are 1.5 mm apart. When the slits are illuminated by a monochromatic light source and the screen is kept 1 m apart from the slits, width of 10 fringes is measured as 3.93 mm. Calculate the wavelength of light used. What will be the width of 10 fringes when the distance between the slits and the screen is increased by 0.5 m. The source of light used remains the same.

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Solution

We know,

Fringe width=λDd

Here fringe width in 1st case =3.9310=0.393mm

D=1000mm, d=1.5mm

λ=0.393×1.51000=3.393×1.510000

λ=5.0895×104mm

=508.95nm

Now , fringe width of 10 fringes when d=1.5+0.5=2.0m

Let initial and final fringe width of 10 fringes be fi,ff

fiff=dfdi=21.5=43


ff=3.93×43=52.4mm


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