Question

In a zero order reaction, for every $10{}^{\circ }C$ rise in temperature, the rate is doubled. If the temperature is increased from $10{}^{\circ }C$ to $100{}^{\circ }C$, the rate of the reaction will be:

• A. 256 times
• B. 512 times
• C. 64 times
• D. 128 times

Answer 1

The correct option is B 512 times

Given, at $10{}^{\circ }C$ rise, rate increases by 2 times.

$\therefore \frac{r_{100{}^{\circ }C}}{r_{10{}^{\circ }C}}=2^{\left(\frac{100-10}{10}\right)}=2^9=512times$.