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Question

In a zero order reaction for every $$10^o$$ rise of temperature, the rate is doubled. If the temperature is increased form $$10^o$$C to $$100^o$$C, the rate of reaction will become:


A
256 times
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B
512 times
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C
64 times
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D
128 times
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Solution

The correct option is B $$512$$ times
For rise in temperature, $$n=1$$
Therefore rate $$=2^n=2^1=2$$
When temperature is increased from $${10^ \circ }C$$ to $${100^ \circ }C$$    change in temperature $$ = 100 - 10 = {90^ \circ }C$$ therefore $$n=9$$ therefore, rate $$=2^9=512$$ times.


Chemistry

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