Question

In AC circuit a resistance of $R\Omega$ is connected in series with an inductance $L$. If the phase difference between the current and voltage is ${45}^o$, the inductive reactance will be

• A. $R/2$
• B. $R/4$
• C. $R$
• D. None of these

Answer 1

The correct option is C $R$

Phase difference in $R-L$ circuit,
$\varphi ={\tan }^{-1}\left(\frac{X_L}{R}\right)$
Given : $\varphi ={45}^o$
$\therefore \tan {45}^o=\frac{X_L}{R}$
$⟹X_L=R$