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In acidic medium, H2O2 changes Cr2O27 to CrO5 which has two ( - O - O -) bonds. Oxidation state of Cr in CrO5 is


A
5
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B
3
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C
6
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D
-10
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Solution

The correct option is C 6
CrO5 has butterfly structure having two peroxo bonds.

Peroxo oxygen has -1 oxidation state.
Let oxidation state of Cr be 'x'
CrO5:x+4(1)+1(2)=0x=+6
 

Chemistry

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