In acidic medium if potassium permanganate is used as an oxidizing agent, we get

M n O_{4}^{2 -}

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M n^{2 +}

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M n O_{2}

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M n_{2} O_{3}

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Solution

The correct option is B $M n^{2 +}$
$M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O$

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Similar questions

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In acidic medium if potassium permanganate is used as an oxidizing agent, we get

The correct option is B Mn2+MnO−4+8H++5e−→Mn2++4H2O

The correct option is B $M n^{2 +}$
$M n O_{4}^{-} + 8 H^{+} + 5 e^{-} \to M n^{2 +} + 4 H_{2} O$