In an A.P., first term is 1, last term is 11 and sum of n terms is 36, then n=
5
6
7
8
n2 (2a + (n-1)d) = 36, here a = 1, a + (n - 1)d = 11 ⇒ n = 6
In an A.P., first term is 1, last term is 11 and sum of n terms is 36, then n =
In an AP, the first term is 8, nth term is 33 and the sum of first n terms is 123. Thn, d = ? (a) 5 (b) −5 (c) 7 (d) 3
The first and last term of an ap are 1 and 11 if the sum of its terms is 36 then a = ______,d=_____,n=_____&an=_________