In an $A C$ circuit the applied potential difference and the current flowing are given by:
$V = 200 sin 100 t$ volt, $I = 5 sin (100 t - \frac{π}{2})$ amp.
The power consumption is equal to:

1000 W

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40 W

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20 W

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zero

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Solution

The correct option is D zero
$ϕ = 90^{o}$ between $V$ and $I$ functions.
$∴ P = V_{r m s} I_{r m s} cos ϕ = 0$

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Similar questions

I = 5 sin (100 t - π / 2)

V = 200 sin (100 t)

A C

i = 5 sin (100 t - \frac{π}{2})

V = 200 sin (100 t)

V

i = 5 s i n (100 t - \frac{π}{2})

V = 200 s i n (100) v o l t .

l = 5 sin (100 t - \frac{π}{2}) A

V = 200 sin (100 t)

[100 t + \frac{π}{2}] a m p

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