Question

In an AC circuit, the potential difference across a capacitor and resistor are $12V$ and $5V$ respectively which are connected in series with an AC source. The peak voltage across the circuit is: (Consider source voltage is of sinusoidal form)

Answer 1

Let the RMS voltage be $E_{rms}$

$E_{rms}=\sqrt{v_c^2+v_R^2}=\sqrt{{12}^2+5^2}=13V$

$E_{rms}$$=\frac{Epeak}{\sqrt{2}}$

$E_{rms}\sqrt{2}=E_{peak}=(13\times \sqrt{2})V=13\sqrt{2}V$