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Question

In an ammeter, 0.2% of main current passes through the galvanometer. If resistance of galvanometer is G, then the resistance of ammeter will be -

A
1499G
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B
499500G
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C
1500G
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D
500499G
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Solution

The correct option is C 1500G

From circuit diagram, potential difference is same across both resistances, then
(2I1000)G=(998I1000)SS=G499
Total resistance of ammeter,
R=SGS+G=(G499)G(G499)+G=G500

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