The correct option is A 0.080N Ba(NO3)2
In Ba(NO3)2 the molar ratio of Ba(NO3)2 to NO−3 is 1 : 2.
Therefore, the molarity of the Ba(NO3)2 solution is
12×0.080=0.040 M
As n - factor of Ba(NO3)2 is 2, its normality will be 0.080 N as normality= molarity × valency factor.
So, the correct answer will be option (c).