Question

In an election, $10\%$ of the people in the voter's list did not participate $60$ votes were declared invalid. There are only two candidates $A$ and $B$, $A$ defeated $B$ by $308$ votes It has found that $47\%$ of the people listed in the voter's list voted for $A$. Find the total number of votes polled.

• A. $6200$
• B. $5580$
• C. $6000$
• D. $7200$

Answer 1

Answer: (B)

$5580$

Let the number of votes $A$ gets $=x$

Then, by the given condition,

the number of votes $B$ gets $=x-308$.

$60$ votes were invalid.

$\therefore$ The total number of votes polled $=x+x-308+60=2x-248$........(i)

$10\%$ of the listed population refrained from voting.

$\therefore$ $(100-10)\%=90\%$ of the listed population took part in the election.

So, the total number of the listed population $=$ $(2x-248)\times \frac{100}{90}=\frac{20x-2480}{9}.$

$47\%$ of this population voted for $A$.

$\therefore$ $A$ got $\frac{20x-2480}{9}\times \frac{47}{100}=x$

$\Rightarrow 47(20x-2480)=900x$

$\Rightarrow 40x=116560$

$\Rightarrow x=2914$

So, the total number of votes polled $=2x-248$ .....(from i)

$=$ $2\times 2914-248=5580$

Ans- Option B.