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Question

In an electromagnetic wave, the amplitude of electric field is 1 V/m. the frequency of wave is 5× 1014Hz. The wave is propagating along z-axis. The average energy density of electric field, in Joulem3, will be


A
1.1 X 10-11
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B
2.2 X 10-12
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C
3.3 X 10-13
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D
4.4 X 10-14
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Solution

The correct option is B 2.2 X 10-12

Average energy density of electric field is given by

ue=12ϵ0E2=12ϵ0(E02)2=14ϵ0E20

=14× 8.85× 1012(1)2=2.2× 1012J/m3.


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