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Question

In an examination a candidate attempts 90% of the  questions. Out of these 70% of his answers are correct. Each questions carries 3 marks for the correct answers and -1 mark for the wrong answer. If the marks secured by the candidate is 243, what is the total number of questions? 


Solution

Let total No. of question be x

So, questions attempted = 90x/100 = 9x/10
Correct questions answered = 70%  of 9x/10 = 63x/100
therefore, wrong answered = 30% of 9x/10 = 27x/100

Marks for correct answer =  3 * 63x/100 = 189x/100
Marks deducted for wrong answer = 1 * 27x/100 = 27x/100

by question, (189x/100) - (27x/100)  =  243
or 162x/100 = 243
hence x = (243*100)/162 = 150 ns.

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