wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In an examination, a candidate had to answer 25 questions each requiring a single answer 'True' or 'False'. It was marked by giving 2 marks for each correct answer and 1 for each incorrect answer.
Write down a formula for the marks, m, obtained by a candidate who answered all the questions but had only x of them correct.

A
m=x2+42
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
m=2x285
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
m=3x25
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
m=2x+32
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C m=3x25
Let x be the number of correctly solved qsns, then 25x will be the incorrectly solved qsns.
Let d m be the total marks got
So, m=2x1(25x)
m=2x25+x
m=3x25

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Counting Principle
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon