Given, total display boards = 24
Length of one display boards =1 m+50 cm=1 m + 50100m [1 m=100 cm]
=(1+0.5) m=1.5 m
Breadth of one display board = 1 m
[0.5 mark]
∴ Perimeter of one display = 2×(Length + Breadth)
=2×(1.5+1) m=(2×2.5) m=5 m
[1.5 mark]
Length of strip = 100 m
Now, number of boards will be framed = Length of stripPerimeter one board =1005 = 20
[1.5 mark]
This means that out of 24 only 20 boards will be framed.
Number of boards left unframed =24−20=4
∴ Length of the strip required for remaining boards = 4× Perimeter of one board
= 4 × 5 = 20 m
[1.5 marks]