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Question

In an experiment, 4 g of M2Ox oxide was reduced to 2.8 g of the metal. If the atomic mass of the metal is 56gmol1. The number of Oatoms in the oxide is:

A
1
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B
4816
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C
5832
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D
4
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Solution

The correct option is B 4816
M2Ox2M+x/2O2
4g2.8g
2×56+x×162×56
4×2×56=2.8(2×56+x×16)
x=4816
Number of oxygen atoms in oxide
x=4816.

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