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Question

In an experiment on photoelectric effect, the separation between emitter and the collector plates is 10cm. Plates are connected through an ammeter without any cell. A magnetic field B exists parallel to the plates. The work function of the emitter is 2.39eV and the light of wavelengths between 400nm and 600nm is incident on it. If minimum value of B for which the current registered by the ammeter is zero is n×106T. Then find out value of n (Neglect any effect of space charge). (assume emission of photo electron to be radomly every possible direction)
1032870_4c9a7d819529421c895f8ba2225f8878.png

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Solution

Here; Φ0=2.39eV
λ1=400nm and λ2=600nm
For B to be minimum Energy should be Maximum
λ sgould be minimum
Here; E=hcλΦ0
=3.0152.39
=0.715eV
The presence of M.field will bend the beam there will be no current if the electron does'not reach the other plates.
r=mvqBr=2mEqB
B=2×9.1×1031×1.6×1019×0.7151.6×1019×0.1
=2.85×105
=0.285×106Tesla

1327045_1032870_ans_f105f03ef8c5436a953b9d86ff84aebd.png

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