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Question
In an experiment, the following reaction takes place:
C(s)+O2(g)→CO2(g)
Determine the mass of carbon dioxide produced, when 12 g of carbon reacts with 48 g of oxygen?
In an experiment, the following reaction takes place:
C(s)+O2(g)→CO2(g)
Determine the mass of carbon dioxide produced, when 12 g of carbon reacts with 48 g of oxygen?
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Solution
The correct option is B 44 g
- Elements always combine together in a constant ratio by mass to form a compound.
- From the given equation, we can see that 1 mole of carbon reacts with 1 mole of oxygen gas, i.e., 12 g of carbon reacts with 32 g of oxygen, so the mass ratio is 12:32 or 3:8.
- This means that carbon will always combine with oxygen in 3:8 by mass to form carbon dioxide.
- Hence, out of 48 g of oxygen, 12 g of carbon will combine with only 32 g of oxygen, and produce 44 g of carbon dioxide (i.e., 48-32 = 16 g of oxygen will remain unreacted).
- Elements always combine together in a constant ratio by mass to form a compound.
- From the given equation, we can see that 1 mole of carbon reacts with 1 mole of oxygen gas, i.e., 12 g of carbon reacts with 32 g of oxygen, so the mass ratio is 12:32 or 3:8.
- This means that carbon will always combine with oxygen in 3:8 by mass to form carbon dioxide.
- Hence, out of 48 g of oxygen, 12 g of carbon will combine with only 32 g of oxygen, and produce 44 g of carbon dioxide (i.e., 48-32 = 16 g of oxygen will remain unreacted).
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