Question

# In an isobaric reversible process, the ratio of heat supplied to the system (dq) and work done by the system (dW) for a ideal monoatomic gas is:

Solution

## At constant pressure, (isobaric process) heat supplied is given as: qp=nCpdT Cp for a monoatomic gas = 52R So, qp=52nR dT Work done by system is given as: dw=nR dT Hence, the ratio is: dqdw=(5/2)nR dTnR dT =52=2.5

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