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Question

In an isosceles triangle, the vertex angle is 14th of each of the equal angles. Find the angle of the triangle.
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Solution

Vertex angle (α)=14th of each of the equal angles.
Let equal angle =β
So, α=β4
β=4α
So, α+β+β=180°
α+4α+4α=180°
9α=180°
α=20° β=80°
Hence, the answer is α=20°,β=80°.


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