In an isosceles triangle, the vertex angle is twice the base angle. (Let the base angle be $b$ in degrees. Remember that the sum of angles of a triangle is 180 degrees).

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Solution

Let the base angle $= b$

$\Rightarrow$ vertex angle $= 2 b$

Sum of angles in a triangle = $180^{\circ}$

$\Rightarrow b + b + 2 b = 180$

$\Rightarrow b = 45^{\circ}$

Angles = $(45^{\circ}, 45^{\circ}, 90^{\circ})$

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Set up an equation in the following case:
In an isosceles triangle, the vertex angle is twice either base angle. (Let the base angle be $b$ in degrees. Remember that the sum of angles of a triangle is $180^{\circ}$ . )

(a) What is the value of x in the figure given below if it is known that perimeter of the triangle is 86?

(b) Set up an equation in the following case and find the value of the unknown:
In an isosceles triangle, the vertex angle is twice either base angle. (Let the base angle be b in degrees. Remember that the sum of angles of a triangle is 180 degrees). [3 MARKS]

Q. In an isosceles triangle, the base angles are equal. The vertex angle is

40^{o}

. What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is

180^{o}

Q. Question 2(b)
Solve the following :
In an isosceles triangle, the base angles are equal. The vertex angle is

40^{\circ}

. What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is

180^{\circ}

Q. In an isosceles triangle, the vertex angle is twice the sum of the base angles. Find the angles of the triangle.

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In an isosceles triangle, the vertex angle is twice the base angle. (Let the base angle be b in degrees. Remember that the sum of angles of a triangle is 180 degrees).

Let the base angle =b⇒vertex angle =2bSum of angles in a triangle =180∘⇒b+b+2b=180⇒b=45∘Angles =(45∘,45∘,90∘)

In an isosceles triangle, the vertex angle is twice the base angle. (Let the base angle be $b$ in degrees. Remember that the sum of angles of a triangle is 180 degrees).

Let the base angle $= b$

$\Rightarrow$ vertex angle $= 2 b$

Sum of angles in a triangle = $180^{\circ}$

$\Rightarrow b + b + 2 b = 180$

$\Rightarrow b = 45^{\circ}$

Angles = $(45^{\circ}, 45^{\circ}, 90^{\circ})$