CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In an octagon ABCDEFGH of equal sides, what is the sum of AB+AC+AD+AE+AF+AG+AH if AO=2^i+3^j4^k ?

A
16^i+24^j32^k
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
16^i24^j32^k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
16^i24^j+32^k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
16^i+24^j+32^k
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

Step 1: Given that:

An octagon ABCDEFGH with centre O.

In which, AB= BC= CD = DE= EF= FG= GH= HA


AO=2^i+3^j4^k

Step 2: Formula used:

According to the triangle law of vector addition;

If two vectors P and Q are represented by the sides AB and BC of as a triangle in both magnitude and direction then the resultant of both the vectors is represented in magnitude and direction by the third side of the triangle taken in the opposite order that is by AC.


Step 2: Calculation of AB+AC+AD+AE+AF+AG+AH

Joining all the vertices of the octagon with point O, we have;


All the sides, in each part of the octagon, are represented by a vector.

Therefore, using triangle law of vector addition, we get;

AO+OB=AB.........(1)

AO+OC=AC..........(2)

AO+OD=AD.........(3)

AO+OE=AE..........(4)

AO+OF=AF.........(5)

AO+OG=AG.........(6)

AO+OH=AH.........(7)

Now,

OA=OEandAO=OE

OB=OF

OC=OG

OD=OH

Using these values and adding equations (1). (2), (3), (4), (5), (6) and (7), we get

7AO+AO=AB+AC+AD+AE+AF+AG+AH

8AO=AB+AC+AD+AE+AF+AG+AH...........(8)

Putting the value of AO , in equation (8) we get;

AB+AC+AD+AE+AF+AG+AH=8(2^i+3^j4^k)

AB+AC+AD+AE+AF+AG+AH=16^i+24^j32^k

Thus,

The value of AB+AC+AD+AE+AF+AG+AH=16^i+24^j32^k


flag
Suggest Corrections
thumbs-up
97
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon